If a building has 5 stories, floor area per story is 8,000 sf, and the lot area is 60,000 sf, what is the FAR?

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Multiple Choice

If a building has 5 stories, floor area per story is 8,000 sf, and the lot area is 60,000 sf, what is the FAR?

Explanation:
FAR compares how much total floor area a building has to the size of the lot, showing how densely the site is developed. First find the total floor area by multiplying stories by floor area per story: 5 × 8,000 = 40,000 square feet. Then divide by the lot area: 40,000 ÷ 60,000 = 0.666..., which rounds to 0.67. So the FAR is about 0.67. This means the building’s total floor area equals roughly 67% of the lot size. Values like 0.50 or 1.00 would require different total floor areas (30,000 or 60,000 sf, respectively), so they don’t match this scenario.

FAR compares how much total floor area a building has to the size of the lot, showing how densely the site is developed. First find the total floor area by multiplying stories by floor area per story: 5 × 8,000 = 40,000 square feet. Then divide by the lot area: 40,000 ÷ 60,000 = 0.666..., which rounds to 0.67. So the FAR is about 0.67. This means the building’s total floor area equals roughly 67% of the lot size. Values like 0.50 or 1.00 would require different total floor areas (30,000 or 60,000 sf, respectively), so they don’t match this scenario.

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